Question

How many grams of nitrogen are contained in a sample of C4H9N3O2 that also contains 9.42x10^24 hydrogen atoms?

Answer 1

73.02 grams

Explanations:

Given the following parameter

Atom of hydrogen = 9.42x10^24 atoms

From the given compound, for every 9 moles of hydrogen, there are 3 moles of nitrogen, hence the atoms of nitrogen present in the compound will be:

`\begin{gathered} atoms\text{ of nitrogen}=(3)/(9)*9.42*10^(24) \\ atoms\text{ of nitrogen}=3.14*10^(24)atoms \end{gathered}`

Convert atoms to moles

`\begin{gathered} moles\text{ of nitrogen}=(3.14*10^(24))/(6.02*10^(23)) \\ moles\text{ of nitrogen}=0.521*10 \\ moles\text{ of nitrogen}=5.21moles \end{gathered}`

Convert moles of nitrogen to mass

`\begin{gathered} mass\text{ of nitrogen}=mole* molar\text{ mass} \\ mass\text{ of nitrogen}=5.21moles*(14g)/(mol) \\ mass\text{ of nitrogen}=73.02grams \end{gathered}`

Hence the mass of nitrogen contained in the sample is 73.02 grams