Question

Y^2 +2y+24 / y+6 Long division

Answer 1

in order to apply the log division, first, we need to divide the leading terms of both dividend and divisor,

`(y^2)/(y)=y`

then, we use this as the first term of our result,

then, we multiply by the divisor and subtract to the dividend,

repeat the same as before using the leading term of the result obtained,

`-(4y)/(y)=-4`

then,

Answer:

The result of the division is:

`(y^2+y+24)/(y+6)=y-4+(48)/(y+6)`