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What is the coordinate of the center of the following circle: x2 + 2x + y2 − 8y − 6 = 0

User Tim Hofman
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1 Answer

6 votes

We will have the following:


x^2-2x+y^2-8y-6=0\Rightarrow(x-1)^2+(y-4)^2=23

So, the center of the circle is located at (1, 4).

User Chris Cruz
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