Question

A spinner is spun 20 times. The spinner has 4 colored sections of equal size. The table shows the results red= 4black= 6 blue= 3green=7 What is the experimental probably of not stopping on the color blue? Leave your answer as a reduced fraction (numerator/denominaton,

Answer 1

Given:

Number of times the spinner is spun, n = 20 times

Number of colored sections = 4

We have the table:

Red = 4

Black = 6

Blue = 3

Green = 7

Let's find the probability the spinner does not stop on the blue color.

To find the probability, apply the formula:

`P(\text{not blue) = 1 - P(blue)}`

To find P(blue), we have:

`P(\text{blue)}=\frac{\text{Number of blue}}{\text{Total number of times the spinner is spun}}=(3)/(20)`

Thus, we have:

`\begin{gathered} P(\text{not blue)= 1 - }(3)/(20) \\ \\ =\text{ }(1)/(1)-(3)/(20) \\ \\ =(20-3)/(20) \\ \\ =(17)/(20) \end{gathered}`

Therefore, the experimemtal probability of not stopping on the color blue is 17/20

ANSWER:

`(17)/(20)`