A system of the linear equation can be consistent independent, consistent dependent, or inconsistent depending on its solution.
System A :
We have the equations:
![\begin{gathered} y\text{ = -2x - 3 (line 1)} \\ y\text{ = -2x + 1 (line 2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1sfg2l2qcnbts4rz8bryzck7zuyar82kjy.png)
We can see that the lines have a similar slope, hence they are parallel. This is shown on the graph.
Hence, the system of equations is inconsistent.
This means that the system has no solution.
System B
We have the equations:
![\begin{gathered} y\text{ = 2x (line 1)} \\ y\text{ = }(1)/(2)x\text{ - }(3)/(2)\text{ (line 2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/sefid1m3ijqsomj480jf3qdo9tujrj718z.png)
From the graph, the lines intersect at only one point (-1, -2).
Hence, the system of equations is consistent independent
This means that the system has a unique solution
Solution : (-1, -2).
System C
We have the equations:
![\begin{gathered} y\text{ = }-3x\text{ (line 1)} \\ 3x\text{ + y = 0 (line 2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/v0qas83oxqf4rbst3j54mrv1cr5ijfupgk.png)
Re-writing the equation for line 2, we have:
![\begin{gathered} y\text{ = -3x (line 1)} \\ y\text{ = -3x (line 2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vwaegvfgrbf1ibwwpqtpxienublc6ybnkw.png)
From the graph, one line lies on top of the other.
Hence, the system of equations is consistent dependent.
This means that the system has infinitely many solutions.