Question

M is the midpoint of the line AB. Endpoint A is (4,2). midpoint M is (6,0). find endpoint B.

Answer 1

`\begin{gathered} \text{ If A= (x1,y1) and B=(x2,y2) then the midpoint M has coordinates} \\ M=(\frac{x_1+x_2_{}}{2},(y_1+y_2)/(2)_{}) \\ \text{ Since M=(6,0) and A=(4,2)} \\ 6=(4+x_2)/(2),0=(2+y_2)/(2) \\ So\text{ } \\ 6\cdot2=4+x_2\text{ And }0=2+y_2 \\ 12-4=x_2\text{ And }-2=y_2_{} \\ x_2=8,y_2=-2 \\ B=(8,-2) \end{gathered}`

So the answer is B=(8,-2)