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A 1500 kg car drives around a flat 200-m-diameter circulartrack at 25 m/s. What are the magnitude and direction of the netforce on the car? What causes this force?

User MMontu
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Given:

The mass of the car is m = 1500 kg

The speed of the car is v = 25 m/s

The diameter of the circular track is d = 200 m.

To find the magnitude and direction of the net force.

The cause of force.

Step-by-step explanation:

The magnitude of force will be


\begin{gathered} F=(mv^2)/(r) \\ =(1500*(25)^2)/(((200)/(2))) \\ =9375\text{ N} \end{gathered}

The direction of the force will be towards the center as this is centripetal force.

Due to circular motion, the centripetal force occurs.

User Luan Fonseca
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