we have the system
2x - 4y = 6 -------> equation A
-5x - 20y = - 15 -----> equation B
Solve by elimination
so
Multiply equation A by -5 both sides
-5*[2x - 4y = 6] -----> -10x+20y=-30 -------> equation C
step 2
Adds equation C and equation B
-10x+20y=-30
-5x - 20y = - 15
------------------------
-15x=-45
x=3
Find out the value of y
substitute the value of x in any equation
2(3) - 4y = 6
6-4y=6
-4y=6-6
-4y=0
y=0
therefore
the solution is (3,0)