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(4)/(3)x-(1)/(3)=9
\begin{gathered} (4)/(3)x=9+(1)/(3) \\ (4)/(3)x=(27+1)/(3) \\ (4)/(3)x=(28)/(3) \\ \text{cross multily} \\ 12x=84 \\ x=(84)/(12) \\ x=7 \end{gathered}

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