500 ml of water at 10°C
m1= 500 ml
T1 = 10°C
100 ml of water at 70°C
m2= 100 ml
T2 = 70°
Heat gained = heat lost
m1 C (T-T1 ) = m2 C (T2- T)
m1 (T-T1 ) = m2 (T2-T)
500 ( T - 10 ) = 100 (70 - T)
Solve for T
500T - 5000 = 7000- 100T
500T +100 T = 7000+5000
600 T = 12000
T= 12000/600
T= 20
Final temperature = 20°C (option B)