Question

A boy sledding down a hill accelerated at 1.35m/s^2. If he started from rest, in what distance would he reach a speed of 5.80m/s?

Answer 1

The final speed of the person can be expressed as,

`v^2=u^2+2as`

Initially the person is at rest therefore, the initial speed of the person is zero.

Plug in the known values,

`\begin{gathered} (5.80m/s)^2=(0m/s)^2+2(1.35m/s^2)s \\ s=((5.80m/s)^2)/(2(1.35m/s^2)) \\ =12.46\text{ m} \end{gathered}`

Therefore, the distance covered by the person is 12.46 m.