Question 1

range,mean,median,and mode. for each set of data find a range,mean,median,and mode. round to the nearest tenth is necessary. data:46,22,46,49,45,39,40,42,41,39,40,36range:_______________median:_________________ mean:________________mode:________________

Question 2

$\begin{gathered} \text{data: 46,22,46,49,45,39,40,42,41,39,40,36} \\ \text{if you arrange these numbers from lowest to highest:} \end{gathered}$
$\begin{gathered} 22,36,39,39,40,40,41,42,45,46,46,49 \\ \text{range}=\text{maximun value-minum value} \\ \text{range}=49-22 \\ \text{range}=27 \end{gathered}$
$\begin{gathered} \operatorname{median}\text{ is the number in the middle of the ordered list} \\ IN\text{ this case they are 40 and 41, hence} \\ we\text{ ne}ed\text{ to promediate those numbers} \\ (40+41)/(2)=40.5 \\ by\text{ rounding up, the median is 41} \end{gathered}$
$\begin{gathered} \text{the mean is the average, in this case} \\ \operatorname{mean}=(22+36+39+39+40+40+41+42+45+46+46+49)/(12) \\ \operatorname{mean}=(485)/(12) \\ \operatorname{mean}=40.4166 \\ by\text{ rouding down} \\ \operatorname{mean}=40.4 \end{gathered}$
$\begin{gathered} \text{the mode is the number (or numbers) which appears more often in the list.} \\ IN\text{ this case, they are 39, 40 and 46. They are repeated 2 times each one of them} \\ so\text{ the data are trimodal} \end{gathered}$

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