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the large ferris wheel makes one revolution in 60 seconds the small ferris wheel makes one revolution in 20 seconds. how many seconds will pass before jeremy and deborah are.both at the bottom again. Jeremy gets on at the bottom of the large ferriss wheels and Deborah gets on at the bottom of the small ferris wheel

User Jackelin
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1 Answer

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To know how many second will pass before jeremy and deborah are.both at the bottom again, we need to calculate the least commom multiple of 20 and 60.

So, the multiples of 20 are: 20, 40, 60, 80, 100, 120, ...

And the multiples of 60 are: 60, 120, 180, 240, 300, ...

Then, the multiples of both 20 and 60 are: 60, 120, 180, 240,...

From those multiples 60 is the minimun one. SO, the least common multiple of 20 and 60 is 60

It means that after 60 seconds Jeremy and Deborah ar

User Cezarlamann
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