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In deltaEFG , e=690 cm, f=650 cm and

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Hello

To solve this question, it would be easier if we draw the triangle.

To solve for this, we would use Cosine rule. This is because, we have the values of two sides and one angle.


\begin{gathered} G^2=E^2+F^2-2EF\cos g \\ G^2=690^2+650^2-2*690*650\cos 58 \\ G^2=476100+422500-475337.580 \\ G^2=423262.42 \\ G=\sqrt[]{423262.42} \\ G=650.59\operatorname{cm}\approx651\operatorname{cm} \end{gathered}

from the calculations above, the value of G is equal to 651cm

In deltaEFG , e=690 cm, f=650 cm and-example-1
User Tunguski
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