Question

Water of mass 3kg at temperature of 80°cis added to 5Kg of water at 5°c Calculatethe final temperature of the mixture

Answer 1

Use the following formula for the amount of heat absorbed:

`Q=mc(T_-T_o)`

where m is the mass, c is the specific heat of water, To is the initial temperature and T is the final temperature.

Take into account that the amount of heat absorbed by water at 5°C comes from the water at 80°C. Then, you can write:

`\begin{gathered} Q_1=-Q_2 \\ m_1c(T-T_(o1))=-m_2c(T-T_(o2)) \end{gathered}`

where,

m1 = 5kg

To1 = 5°C

m2 = 3kg

To2 = 80°C

You can cancel specific heat c in the last equation, solve for T, replace the values of the other parameters and simplify, as follow: