Question

(calc !) the amount of carbon dioxide in moles produced in a chemical reaction is given by the function f(t)= 0.02x^2 + 0.5. if t is in seconds find the rate of production of carbon dioxide after 2 seconds

Answer 1

The amount of carbon dioxide is given by the following function:

`f(t)=0.02*t^2+0.5`

The rate of production of carbon dioxide is going to be:

`(d(f(t)))/(dt)=(d)/(dt)(0.02t^2+0.5)`
`(df(t))/(dt)=2*0.02*t^(2-1)+0`

Replacing t=2.

`\begin{gathered} (df(t))/(dt)=2*0.02*t^1 \\ (df(2))/(dt)=2*0.02*(2)^1=0.08 \end{gathered}`

Answer: The rate of production of carbon dioxide after two seconds is

C) 0.08mol/s.