
Step-by-step explanation:


Using elimination method:
multiply equation 2 by 2
2(x) + 2(4y) = 2(5)
2x + 8y = 10 ...equation 2
combine both equations:
2x + 7y = 2 ...equation 1
2x + 8y = 10 ...equation 2
subtract equation 2 from 1:
2x - 2x + 7y - 8y = 2 - 10
0 - y = -8
-y = -8
y = -8/-1
y = 8
substitute for y in equation 2:
x + 4y = 5
x + 4(8) = 5
x + 32 = 5
x = 5 - 32
x = -27
