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1 vote
What is the slope of line AB, where the points are A (-1,5) and B (3,-1)

User Biker John
by
6.1k points

1 Answer

2 votes


-(3)/(2)

Step-by-step explanation

Step 1

when you have 2 points of a line P1 and P2, you can easily find the slope using:


\begin{gathered} \text{slope}=m=(y_2-y_1)/(x_2-x_1) \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

Let

P1=A=(-1,5)

P2=B=(3,-1)

Step 2

replace


\begin{gathered} \text{slope}=m=(y_2-y_1)/(x_2-x_1) \\ \text{slope}=m=(-1-5)/(3-(-1))=(-6)/(3+1)=(-6)/(4)=-(3)/(2) \end{gathered}

I hope this helps you

User ZPPP
by
7.4k points
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