Given:
$200 - payment for the self-proclaimed psychic
$1.50 - club's earnings for each ticket
Find: club's gain/lose after selling 100 tickets and number of tickets in order to break-even
Solution:
Since x = represents the number of tickets sold, we can say that the profit of the club is y = ($1.50 times the number of tickets x sold) - the payment for the psychic.
![y=1.50x-200](https://img.qammunity.org/2023/formulas/mathematics/college/cpbju8uh7dhey7b1gipfzgg9ihpyhux5bp.png)
a. Let's plugin x = 100 tickets in the formula above.
![y=1.50(100)-200](https://img.qammunity.org/2023/formulas/mathematics/college/2hog4mxu9ke0l3vlb3sjvc51r6uldj9dsn.png)
Then, solve.
![\begin{gathered} y=150-200 \\ y=-50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/obsatok9s4qedlesvbshd3ksqkrmshywp0.png)
Since the answer is negative, by selling 100 tickets, the club loses $50.
b. Break-even means there is no gain nor lose. Hence, the charge and the earnings of the club are equal. So, with this, we will assume that y = 0.
![0=1.50x-200](https://img.qammunity.org/2023/formulas/mathematics/college/53ncl0asb60j4d3ig5h6kh2wb2gvrg5mws.png)
Then, we can solve for x or the number of tickets needed.
Add 200 on both sides of the equation.
![\begin{gathered} 0+200=1.50x-200+200 \\ 200=1.50x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jxnj4wt7pn66uni1zgfut2ablj48wo7l26.png)
Divide both sides by 1.50.
![\begin{gathered} (200)/(1.50)=(1.50x)/(1.50) \\ 133.33=x \\ 133\approx x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6xjbo3p83y8735spzi7utpbnjfmklvudxc.png)
Hence, the club needs to sell 133 tickets in order to break even.