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3. determine what element undergoes oxidation and what element undergoes reduction in 3H2SO4 + 2KMnO4 + 5H2O2 --> 5O2 + 2MnSO4 + 8H2O + K2SO4. Write NA if not applicable. Please fill out table in picture attached4. Place the letter corresponding to each of the reaction types in the column to the right of each chemical reaction. List all that apply. Each reaction my be described by one or two reaction types.

3. determine what element undergoes oxidation and what element undergoes reduction-example-1

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Answer:

Manganese undergoes reduction

Oxygen undergoes oxidation

Explanations

What is oxidation?

3) Oxidation is defined as the loss of electron(s) of an atom or increase in the oxidation state of the atom while Reduction has to do with the gain of electron(s) by an atom and a reduction in the oxidation state of the atom.

Given the chemical reaction


3H_2SO_4+2KMnO_4+5H_2O_2\rightarrow5O_2+2MnSO_4+8H_2O+K_2SO_4

The half ionic reaction for the oxidation-reduction reaction is given as:


\begin{gathered} 2Mn^(7+)+10e^-\rightarrow2Mn^(2+)\text{ \lparen reduction\rparen} \\ 10O^--10e^-\rightarrow10O\text{ \lparen oxidation\rparen} \end{gathered}

From the half-reaction, you can see there is a change in the oxidation state of Manganese from +7 to +2. This shows that Manganese undergoes reduction due to the reduction in its oxidation state.

For the oxygen element, there is a loss of election and an increase in its oxidation state from -1 to 0 showing that the oxygen element undergoes oxidation.

The same is not applicable for other e

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