Question

Factor to find the zeros of the function y = 2x^2 -3x + 1.

Answer 1

Answer:

The zeros of the function are x = 1/2, 1

Step-by-step explanation:

The given function is:

`y=2x^2-3x+1`

This can be factorized as shown below

`\begin{gathered} y=2x^2-2x-x-1 \\ \\ y=2x(x-1)-1(x-1) \\ \\ y=(2x-1)(x-1) \end{gathered}`

To find the zeros of the function, let y = 0

`\begin{gathered} 2x-1=0 \\ 2x=1 \\ x=(1)/(2) \\ \\ \\ x-1=0 \\ x=1 \end{gathered}`

The zeros of the function are x = 1/2, 1