Question

A photon in a laboratory experiment has an energy of 5.0 eV. What is the frequencyof this photon?

Answer 1

`frequency=\text{ 3.47*10}^(15)\text{ Hz}`Step-by-step explanation

frequency is thhe number of waves that crosses a fixed point in one second . The unit of frequency is per second.

Step 1

a) convert the energy into joules

the equivalence is

`1\text{ eV=1.6*10}^(-19)\text{ Joules}`

so, 5 eV, will be 5 times this amount, so

`Energy=5\text{ eV=5*1.6*10}^(-19)=2.3*10^(-18)\text{ Joules}`

Step 2

we also know that, Photon energy(E) is the multiplication of plank's constant (h) and frequency(v)

so

`E=hv`

replace and solve for frequency(v)

`\begin{gathered} E=hv \\ 2.3*10^(-18)=6.63*10^(-34)*v \\ divide\text{ both sides by 6.63*10}^(-34) \\ (2.3*10^(-18))/(6.63*10^(-34))=(6.63*10^(-34)*v)/(6.63*10^(-34)) \\ 3.47*10^(15)=v \end{gathered}`

therefore, the answer is

`frequency=\text{ 3.47*10}^(15)\text{ Hz}`

I hope this helps you