Question

aluminum reacts with chlorine gas to form aluminum chloride according to the reaction below (2AI+3CI2=2AICI3)how many moles of aluminum chloride can be produced from 2.49 L of chlorine gas at a temperature of 23 celsius and a pressure of 2.23 atm?

Answer 1

In this question, we have the following reaction:

2 Al + 3 Cl2 -> 2 AlCl3

Now we need to know how many moles of AlCl3 is produced, according to the information given about Cl2, which are:

2.49 L

23°C, but for our question, we need to use Kelvin, 296 K

2.23 atm of pressure

Now to find the number of moles of Cl2, we will be using the Ideal gas law formula, which is:

PV = nRT

R is the gas constant = 0.082

Now we add the values into the formula:

2.23 * 2.49 = n * 0.082 * 296

5.5527 = 24.272n

n = 4.37 moles of Cl2

Now we know the number of moles of Cl2, in order to find the number of moles of AlCl3, we will use their molar ratio, 3 Cl2 = 2 AlCl3, but we have 4.37 moles of Cl2, therefore:

3 Cl2 = 2 AlCl3

4.37 Cl2 = x AlCl3

x = 2.91 moles of AlCl3 are produced