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Each letter of the word "thunderstorm" has been written on a separate slip of paper and put into a box. Find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement?

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SOLUTION

From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.

This means the probability of selecting t and r.

That is


P(t)* P(r)

There are 12 letters (total outcomes). And there are 2r and 2t.

So probability becomes


\begin{gathered} \frac{possible\text{ outcome}}{\text{total outcome }} \\ P(t)=(2)/(12) \\ P(r)=(2)/(12) \\ P(t)* P(r)=(2)/(12)*(2)/(12) \\ =(1)/(6)*(1)/(6) \\ =(1)/(36) \end{gathered}

Hence the answer is


(1)/(36)

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