SOLUTION
We want to solve
![12(1)/(2)*4](https://img.qammunity.org/2023/formulas/mathematics/high-school/nnieyamgnn1djsq7ht3fbeuzzjx4cfh7u8.png)
To do this, change the mixed fraction into improper fraction.
We say, 2 multiplied by 12, then plus 1. We write the result as the numerator over the denominator which is 2. That is
![\begin{gathered} 12(1)/(2)\text{ to improper fraction becomes } \\ 2*12=24 \\ 24=1=25.\text{ this becomes } \\ (25)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dk4astfqfci7bzsp3wg0siy3cegbn7m9qk.png)
We then multiply by 4, we have
![\begin{gathered} (25)/(2)*4 \\ This\text{ becomes } \\ (25)/(2)*(4)/(1) \\ 2\text{ cancels itself is 1, and into 4, it is 2. So we have } \\ (25)/(1)*(2)/(1) \\ =(25*2)/(1*1) \\ =(50)/(1) \\ =50 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/rz9l43xipl2nj3uocnmelezujlap0b406k.png)
Hence the answer is 50