Answer:
To convert the polar equation to a rectangular equation.
Then to graph using rectangualr equation.
Given polar equation is,
![r=\sin \theta](https://img.qammunity.org/2023/formulas/mathematics/college/g6b7sl4nehts9tg5o8pbczepi5mpmn4grh.png)
We know that,
A polar coordinate system, gives the co-ordinates of a point with reference to a
point O and a half line or ray starting at the point O.A point P in the plane, has polar coordinates (r, θ), where r is the distance of the point from the origin and θ is the angle that the ray |OP| makes with the positive x-axis.
To convert from Polar to Cartesian coordinates, we use the identities:
![\begin{gathered} x=r\cos \theta \\ y=r\sin \theta \\ x^2+y^2=r^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/f2k3sdt9ek92gexsk6afz9kt26c7a6v921.png)
Multiply r to the given polar equation, we get
![r^2=r\sin \theta](https://img.qammunity.org/2023/formulas/mathematics/college/6wvb5him9l2h9yhlevg6h7xy983rx6atj6.png)
Substitute the values in terms of x and y, we get
![x^2+y^2=y](https://img.qammunity.org/2023/formulas/mathematics/college/9oduzl8szihpea28c84qnqw7on0kmniifn.png)
we get,
![x^2+y^2-y=0](https://img.qammunity.org/2023/formulas/mathematics/college/r6vbqed6chvdn8go9yx7ri9djon10nwwyg.png)
On ploting the graph using the above equation we get,