147k views
5 votes
Part A: Simplify the expression. Show all work.Part B: What is the domain of the function? Show all work.Part C: Explain why the expression in the denominator must be set equal to zero when determining the function'sdomain.

Part A: Simplify the expression. Show all work.Part B: What is the domain of the function-example-1
User Tehila
by
5.5k points

1 Answer

3 votes

\begin{gathered} (4)/(6m^2)-(5-m^2)/(4m)=(4\cdot2-(5-m^2)\cdot3m)/(12m^2)=(8-(15m-3m^3))/(12m^2)= \\ =(8-15m-3m^3)/(12m^2) \end{gathered}

B. The domain of a function is the set that contains every possible value for the independent variable (in this case, m). Given that you cannot divide by zero then


\begin{gathered} 12m^2\\e0 \\ m^2\\e0 \\ m\\e0 \end{gathered}

Then, the domain is all real numbers except zero.

C. The expression in the denominator must be set equal to zero because you can't divide by zero.

User Case
by
5.9k points