Question

Simplify to a single trig function with no denominator.1-sinºx

Answer 1

Given:

`1-sin^2x`

Solution

Recall that from trigonometric identities:

`\sin ^2x+cos^2x\text{ = 1}`

Re-arranging, we have:

`\cos ^2x=1-sin^2x`

Hence,

`\begin{gathered} 1-sin^2x=cos^2x \\ \text{Answer : cos}^2x \end{gathered}`