228k views
4 votes
Factor completely.2x^2-50

User Grrussel
by
8.0k points

1 Answer

0 votes

\begin{gathered} 2x^2-50=2(x^2-25) \\ \text{ Remember that a\textasciicircum{}2 - b\textasciicircum{}2 = (a-b)(a+b)} \\ =2(x^2-5^2) \\ =2(x-5)(x+5) \end{gathered}

Te polynomial factors completely as 2(x-5)(x+5)


\begin{gathered} 81-4x^2\text{, since 81 = }9^2\text{, we have} \\ 81-4x^2=9^2-4x^2\text{, but }4=2^2 \\ =9^2-2^2x^2=9^2-(2x)^2^{} \\ =(9-2x)(9+2x) \end{gathered}

User Conor Gallagher
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories