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Using the centripetal acceleration of 6 x 10 ^-3 m/s^2 for the Earth, estimate the force needed for the Earth to stay in the orbit.

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Answer:
F\text{ = 3.5832}*10^(22)NExplanations:

The centripetal acceleration:


a\text{ = 6 }*10^(-3)m\text{/s}^2

The mass of the Earth:


m\text{ = }5.972*10^(24)\operatorname{kg}

The Force needed for the earth to stay in the orbit is given as:

F = ma


\begin{gathered} F\text{ = }5.972*10^(24)*\text{ 6 }*10^(-3) \\ F\text{ = }35.832*10^(24-3) \\ F\text{ = 35.832 }*10^(21) \\ F\text{ = 3.5832}*10^(22)N \end{gathered}

Therefore, the force (F) needed for the earth to stay in the orbit is:


F\text{ = 3.5832}*10^(22)N

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