189k views
1 vote
In a random sample of 200 people, 141 said that they watched educational television. Find the lower limit of the 95% confidence interval of the true proportion of people who watch educational television, rounded to three places after the decimal point.

In a random sample of 200 people, 141 said that they watched educational television-example-1
User Gregn
by
8.0k points

1 Answer

4 votes

First, we have that the proportion given is:


\hat{p}=(141)/(200)=0.705

for a confidence interval with 95% of significance level, we can use the following z value:


z_{(\alpha)/(2)}=1.96

then, the general expression to find the 95% IC for proportions is:


(\hat{p}-1.96,\hat{p}+1.96)

in this case, we have the following:


(0.705-1.96,0.705+1.96)=(-1.255,2.665)

therefore, the lower limit of the confidence interval is -1.255

User Nikolay Rusev
by
9.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories