We know that the total of seats for this case are 61000 so we have the following equation:
![A+B+C=61000](https://img.qammunity.org/2023/formulas/mathematics/college/2zebt2tsg7hx88l86febgvmi37j2o6ryt2.png)
We also know that the number of seats in Secton A equals the total number of seats in sections B and C so then A=B+C
![A+A=61000](https://img.qammunity.org/2023/formulas/mathematics/college/jfr8h7521vzknwap7h33cs5fbcfgg76hxn.png)
Then the value of A =30500
Now we can create a function for the cost and we got:
![3436000=85A+30B+25C](https://img.qammunity.org/2023/formulas/mathematics/college/qa348suq2rk66vxhquqj3ryldzh0q0xuci.png)
Replacing the value of A we got:
![30B+25C=843500](https://img.qammunity.org/2023/formulas/mathematics/college/m7gpcp7f87yhhpx1olyz332p9hv599hqfz.png)
And rewriting the first equation we got:
![B+C=30500](https://img.qammunity.org/2023/formulas/mathematics/college/piuq49zti22pgzauz78vrmrner5bciu5y0.png)
Solving for B we got: B=30500-C and replacing in the before equation we got:
![30(30500-C)+25C=843500](https://img.qammunity.org/2023/formulas/mathematics/college/mkb45c0wbcgvv4cwuuoxv2so9tjym07gwn.png)
And solving for C we got:
![-5C=843500-915000](https://img.qammunity.org/2023/formulas/mathematics/college/4yhk7bgqfdxad2fntx3hzepqwwj1ixtaoz.png)
![C=(71500)/(5)=14300](https://img.qammunity.org/2023/formulas/mathematics/college/ovrf206v5bgxdoy4jdn84bnqo34xjhzh23.png)