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29 votes
29 votes
In ΔNOP, the measure of ∠P=90°, PN = 95 feet, and OP = 31 feet. Find the measure of ∠O to the nearest degree.

User Rits
by
3.2k points

1 Answer

13 votes
13 votes

Given:

In ΔNOP, the measure of ∠P=90°, PN = 95 feet, and OP = 31 feet.

To find:

The measure of ∠O to the nearest degree.

Solution:

In a right angle triangle,


\tan \theta=(Opposite)/(Adjacent)

In triangle NOP,


\tan O=(PN)/(OP)


\tan O=(95)/(31)


O=tan^(-1)(95)/(31)


O=71.92768


O\approx 72

Therefore, the measure of angle O is 72 degrees.

User Danjam
by
3.2k points
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