95.6k views
3 votes
Express y = 4x ^ 2 - 6x + 14 in the form y = 4 * (x - p) ^ 2 + q , where p and q are constants. Hence, state the minimum value of y and the value of x at which the minimum value occurs. Find the equation of the line of symmetry.

Express y = 4x ^ 2 - 6x + 14 in the form y = 4 * (x - p) ^ 2 + q , where p and q are-example-1
User Peonicles
by
8.3k points

1 Answer

1 vote

Answer:

Step-by-step explanation:

Here, we want to write the given equation in the form stated

We proceed as follows:


\begin{gathered} y\text{ = 4x}^2-6x\text{ + 14} \\ y\text{ = 4\lparen x-}(3)/(2))\placeholder{⬚}^2+5 \end{gathered}

Thus, we have it that p has a value of 3/2 and q has a value of 5

Now, we want to state the minimum value of y and x at which the minimum value occurs

The minimum y value would be the value of q which is 5

The value of x at this y-value is p, which is 3/2

Lastly, we want to find the equation of the line of symmetry

Mathematically, we have that as :


x\text{ = -}(b)/(2a)

where, b is the coefficient of x which is -6 and a is the coefficient of x^2 which is 4

Thus, we have the equation of the line of symmetry as:


x\text{ = -}((-6))/(2(4))\text{ = }(6)/(8)\text{ = }(3)/(4)

User Sspross
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories