Question

Balance each chemical reaction below and then classify it as a combination,decomposition, single-displacement, double-displacement or combustion reaction.9A). C6H12 (g) + _ O2 (g) H2O (g) + CO2 (g) class:B) If you had 3.00 mols of oxygen, how many moles of CO2 will you make from the reaction above?

Answer 1

1) C6H12 (g) + O2 (g) --> H2O (g) + CO2 (g)

To balance the chemical reaction you need to have the same amount of atoms of each element on both the reagents and products side.

C6H12 (g) + O2 (g) --> H2O (g) + CO2 (g)

Reactant:

C - 6

H - 12

O - 2

Product:

C - 1

H - 2

O - 2

Now let's equalize the atoms on the products and reagents side:

C6H12 (g) + 9 O2 (g) --> 6 H2O (g) + 6 CO2 (g)

Reactant:

C - 6

H - 12

O - 18

Product:

C - 6

H - 12

O - (6x1) + (6x2) = 18

chemical equation balanced: C6H12 (g) + 9 O2 (g) --> 6 H2O (g) + 6 CO2 (g)

2) C6H12 (g) + 9 O2 (g) --> 6 H2O (g) + 6 CO2 (g) this is a complete combustion reaction, because it has a fuel reacting with oxygen that forms water and carbon dioxide.

class: combustion reaction.

3) B) To answer you need to use the proportion of the chemical equation:

9 moles of O2 = 6 moles of CO2

3 moles of Oxygen = x moles of CO2

9x = 3 × 6

x = 2 moles of CO2