Question

Part II: Workout: Please make sure to clearly show all of your work to receive credit.I6. Solve the following system of equations using the method of your choice.y=- 2x - 3x + 4y =16

Answer 1

Use substitution to solve the system of equations given below.

y = -2x - 3

x +4y = 16

`\begin{gathered} y=-2x-3\ldots\ldots(1) \\ x+4y=16\ldots\ldots.(11) \end{gathered}`

Substitute -2x-3for y in last equation and solve for x. Insert that value into the first equation and solve for y. Check by inserting both values into the second equation.

`\begin{gathered} -7x-12=16 \\ -7x=16+12 \\ -7x=28 \\ \text{divide both side by -7} \\ -(7x)/(-7)=(28)/(-7) \\ x=-4 \end{gathered}`

solve for the value of y be replacing x with -4

`\begin{gathered} y=-2x-3 \\ y=-2(-4)-3 \\ y=8-3 \\ y=5 \end{gathered}`

Hence the solution of the system of equations are (- 4 ,5)

`(x,y)--\longrightarrow(-4,5)`