Given data
The vector in the x-direction is Cx = -105 m
The vector in the y-direction is Cy = - 88.2 m
The expression for the direction of the vector is given as:
![\theta=\tan ^(-1)((C_y)/(C_x))](https://img.qammunity.org/2023/formulas/physics/high-school/fqp9b0vgvdr8dapaxmuik9vckv7mzus2so.png)
Substitute the value in the above equation.
![\begin{gathered} \theta=\tan ^(-1)(\frac{-88.2\text{m}}{-105\text{ m}}) \\ \theta=40^o \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/1jv73nynhy5dva6wyolifbnf4blwhu97eg.png)
Thus, the direction of the vector is 40 degrees.