Question

f a container holds 18 L of gas at 420. K and is cooled to 210.K, at constant pressure and amount of gas, what volume would the container be now?

Answer 1

The new volume would be 9 L

Step-by-step explanation:

Here, we want to get the new volume of the container

Mathematically, the volume and temperature of a given mass of gas is directly proportional according to Charles' law

We have that as:

`(V_1)/(T_1)\text{ = }(V_2)/(T_2)`

where:

V1 is the initial volume which is 18 L

T1 is the initial temperature which is 420 K

V2 is the final volume that we want to calculate

T2 is the final temperature which is 210 K

Substituting the values, we have it that:

`\begin{gathered} (18)/(420)\text{ = }(V_2)/(210) \\ \\ V_2\text{ = }\frac{210\text{ }*18}{420}\text{ = 9 L} \end{gathered}`