Question

An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and

its internal energy increased by 9185 J. What is the specific heat of the gas?

Answer 1

`C=0.596(J)/(g\°C)`

Step-by-step explanation:

Hello there!

In this case, according to the first law of thermodynamics it is possible to compute the gained heat by the water as shown below:

`Q=\Delta U+W\\\\Q=9185J+346J=9531 J`

Thus, it is possible to solve for the specific heat of the gas as shown below:

`Q=mC\Delta T\\\\C=(Q)/(m\Delta T)=(9531J)/(80.0g*(225-25)\°C)\\\\C=0.596(J)/(g\°C)`

Best regards!