Question

What are the vertices of (AABC)when it is translated by x-6, y2), graph thetransformation?A'B'С

Answer 1

`\begin{gathered} A^(\prime)(0,0) \\ B^(\prime)(4,2) \\ C^(\prime)(2,-6) \end{gathered}`

Step-by-step explanation

Step 1

get the coordinates of each point.

Let

`\begin{gathered} A=(-6,2) \\ B=(-2,4) \\ C=(-4,-4) \end{gathered}`

Step 2

now, to get the image apply the rule

`(x,y)\rightarrow(x+6,y-2)`

then

`\begin{gathered} A(-6,2)\rightarrow A´(-6+6,2-2)\rightarrow A^(\prime)(0,0) \\ B(-2,4)\rightarrow B^(\prime)(-2+6,4-2)\rightarrow B^(\prime)(4,2) \\ C(-4,-4)\rightarrow C^(\prime)(-4+6,-4-2)\rightarrow C^(\prime)(2,-6) \end{gathered}`

I hope this helps you