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A manufacturer inspects 400 personal video players and finds that 398 of them have no defects. What is the experimental probability that a video player chosen at random has no defects? Express your answer as a percentage.A. 99.5%B. 99%C. 95%

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EXPLANATION;

We are given the total number of personal video players as 400. Then we are told that upon inspection, it was discovered that 398 has no defects.

First, we need to take note that an experimental probability is a situation whereby we conduct an experiment and use the results to determine the probability of an event occurring.

For the question provided, the total number of outcomes represents the total number of personal video players. The number that has no defects represents the number of required outcomes in this experiment.

The probability of an event E, is given as;


P[E]=\frac{number\text{ }of\text{ required outcomes}}{number\text{ of all possible outcomes}}

Therefore, to calculate the experimental probability of this event;


P[has\text{ }no\text{ }defects]=(398)/(400)
\begin{gathered} To\text{ express this as percentage, we will take the result} \\ arrived\text{ at and convert it to a percentage } \end{gathered}
P[non-defective]=(398)/(400)
P[non-defective]=0.995
P[non-defective]=99.5

To percentage, we now have, 0.995 times 100;

ANSWER:


\begin{gathered} P[non-defective] \\ A:99.5\% \end{gathered}

The correct answer is option A

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