Question

What is the magnetic field if a force of 1.38N is experienced by a 6.12C charge traveling at 7.82m/s?34.7T0.0288T0.567T1.76T

Answer 1

We can find the magnetic field as follows:

`\begin{gathered} B=(F)/(qv) \\ where: \\ q=6.12C \\ v=7.82m/s \\ F=1.38N \\ Therefore: \\ B=(1.38)/(6.12\cdot7.82)=(1.38)/(47.8584) \\ B=0.0288T \end{gathered}`

Answer:

0.0288 T