
1) Since this quadratic equation has an "a" coefficient, the leading one, greater than 0. We can state that this quadratic has a minimum value described by the Vertex of that Parabola.
2) So, we are going to use the following formula to find the Vertex Coordinates:

And now we need to plug that h-coordinate into the quadratic formula to get the "k" coordinate:

And that's the answer: Minimum, V(-5/2,11/2)