Recall that the inner angles of a triangle add up 180 degrees, then we can set the following equation for the given triangle:
![\begin{gathered} 4x+7+3x+13+90=180 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/84bgkbr3yfzmeyrpnvqyar22ipdxtt44av.png)
solving for x we get:
![\begin{gathered} 7x+110=180 \\ 7x=180-110=70 \\ x=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jwowae3d5uohq9jlybsu7wqkelbutahp3h.png)
With the value of x=10, we compute the angles:
4x+7 =47 degrees
3x+13= 43 degrees
Finally the angles of the triangle are:
![47^o,43^o,90^o](https://img.qammunity.org/2023/formulas/mathematics/college/wde3dqmxyzav96njrxiy9qiu3d12gkba72.png)