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Find the expected value of therandom variable with thefollowing probability distribution:23456789101112Р1/361/181/121/95/361/65/361/91/121/181/36[?]
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Find the expected value of therandom variable with thefollowing probability distribution:23456789101112Р1/361/181/121/95/361/65/361/91/121/181/36[?]

Find the expected value of therandom variable with thefollowing probability distribution-example-1
User Avysk
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To find the expected value of this probability distribution, we can use this expression:


\begin{gathered} E(x)=\sum ^{}_{}x\cdot p \\ E(x)=(2)((1)/(36))+(3)((1)/(18))+(4)((1)/(12))+(5)((1)/(9))+(6)((5)/(36))+(7)((1)/(6))+(8)((5)/(36))+(9)((1)/(9))+(10)((1)/(12))+(11)((1)/(18))+(12)((1)/(36)) \end{gathered}

Solving this E(x) is equal to:


E(x)=7

User The Pax Bisonica
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