Question

I need help with this question, like just check the answers please

Answer 1

Part b) To solve this problem, you have to determine the vertex of the parabola represented by the function

`d(t)=160+48t-16t^2.`

To determine the vertex, you have to complete the square, and take the above equation to the following form:

`y=l(x-h)^2+k,`

where (h,k) is the vertex of the parabola.

Completing the square you get:

`\begin{gathered} d(t)=-(16t^2-48t+36)+36+160, \\ d(t)=-(4t-6)^2+196. \end{gathered}`

Without further calculations, we can conclude that the maximum height will be:

`196ft.`

at time:

`t=(6)/(4)=1.5.`

Answer:

`\begin{gathered} height=196ft, \\ time=1.5\text{ seconds.} \end{gathered}`