1 Answer

Singingwolfboy · Answer 1 · 2023-01-23T02:18:01+0000

We have the following expression:

$(x-2)\cdot(x-7)\leq0$

and we want to know the set of values of x that satisfies the inequality.

We see that in order to be the left-hand side of the inequality less or equal to zero we must have:

1) First case.

(x-2) is negative and (x-7) is positive, so its product is a negative number.

$\begin{gathered} (x-2)\leq0 \\ \text{and} \\ (x-7)\ge0 \end{gathered}$

This is equivalent to have:

$\begin{gathered} x\leq2 \\ \text{and} \\ x\ge7 \end{gathered}$

There are no values of x that can satisfy both inequalities at the same time. So this is an incompatible solution.

2) Second case

(x-2) is positive and (x-7) is negative, so its product is a negative number.

$\begin{gathered} (x-2)\ge0 \\ \text{and} \\ (x-7)\leq0 \end{gathered}$

This is equivalent to have:

$\begin{gathered} x\ge2 \\ \text{and} \\ x\leq7 \end{gathered}$

In this case, the inequalities are compatible and the set or range of values of x that satisfies these inequalities are:

$2\leq x\leq7$

Plotting this in the graph:

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