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Find the inverse y = x^2 - 10x

User SnAzBaZ
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\begin{gathered} y=x^2-10x \\ \Rightarrow x^2-10x-y=0 \end{gathered}
\Rightarrow(x-5)^2-(-5)^2-y=0
\begin{gathered} \Rightarrow(x-5)^2=y+25 \\ \Rightarrow x-5=\pm\sqrt[]{y+25} \end{gathered}
\Rightarrow x=\pm\sqrt[]{y+25}+5

Hence the inverse is given by:


y=\pm\sqrt[]{x+25}+5

User Mohamad Elghawi
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