Question

The fifth term of the sequence 1 /(n^2+1) is:

Answer 1

The general term of a sequence is given as:

`a_n=(1)/(n^2+1)`

Where n is the number of the term, starting from n = 1.

It's required to find the fifth term of the sequence, that is, for n = 5. Substitute:

`a_5=(1)/(5^2+1)`

Calculating:

`\begin{gathered} a_5=(1)/(25+1) \\ a_5=(1)/(26) \end{gathered}`

The fifth term is 1/26