Using the first point of question: (x,y) = (0,1), we can discard options A and D because:
• A) y = 3*0^2 = 0 ≠ 1,
,
• D) y = 3*0 - 2 = -2 ≠ 1.
Now, using the second point: (x,y) = (1,3), we can discard option C because:
• C) y = 1 + 1 = 2 ≠ 3.
So the only option that can be correct is option B. We can verify that evaluating for:
• x = 0, we get: y = 2*0 + 1 = 1,
,
• x = 1, we get: y = 2*1 + 1 = 3,
,
• x = 2, we get: y = 2*2 + 1 = 5,
,
• x = 3, we get: y = 2*3 + 1 = 7.
Answer
B. y = 2x + 1